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Specific Heat Calculator

Calculate heat energy transferred using Q = mcΔT. Find heat, mass, specific heat capacity, or temperature change.

J/(kg·K) — water: 4186, iron: 450, aluminum: 900
In °C or K (same value)
In Joules

Results

Result83,720.0,000
Heat (Q)83,720.00 J
Mass (m)1.0,000 kg
Specific Heat (c)4,186.00 J/(kg·K)
Temp Change (ΔT)20.0,000 °C

📖What is it?

The specific heat equation Q = mcΔT quantifies the heat energy (Q) required to change the temperature of a mass (m) by ΔT degrees, given the material's specific heat capacity (c). Specific heat (c) is measured in J/(kg·K). Higher c means a material requires more energy to heat up — water's high c (4186) makes it excellent for thermal regulation.

🎯How to use

Select what you want to solve for from the dropdown. For "Heat (Q)", enter mass, specific heat, and temperature change. For other quantities, enter heat (Q) and the other two knowns.

💡Example scenario

How much heat is needed to warm 1 kg of water by 20°C? Select "Heat (Q)", enter m = 1 kg, c = 4186 J/(kg·K), ΔT = 20°C. Q = 1 × 4186 × 20 = 83,720 J ≈ 83.7 kJ. This is roughly the energy in a 20-calorie snack (1 cal = 4.184 J).

🏆Pro tip

Specific heat reference table: Water = 4186, Sea water = 3993, Ice = 2090, Aluminium = 900, Glass = 840, Iron/Steel = 450, Copper = 385, Gold = 128, Lead = 128 J/(kg·K). Calorimetry uses Q_gained = −Q_lost to find unknown specific heats experimentally. A Calorie (food energy) = 1 kcal = 4184 J.